Blog Week 20

On Monday, we went reviewed what we were talking about on Thursday. We learned that when comparing one element's mass to another, we get a ratio that is unique to those elements. We did some examples and my group got assigned question six, but we didn't finish it completely. We did an equation that is: x=mg, 0.65x=O, x+0.65x=100g and we got the answer earlier and x=60.6g. This picture below shows another example we did. The first part is each element over the whole solution. The second part we divided the top number by the bottom to get a decimal then moved the decimal place over to get a percentage. These percentages where the percentage of each element in the solution.

On Tuesday, we did a lab. We wanted to find how much and how many of each hardware tool we had. We related how much to how many, which for food is serving size, but for our experiment we called it Quinn. We also wanted to find the relative mass of each hardware, which is the mass divided by the smallest mass. The picture below shows the results from the lab. For the Quinns we did the mass of the whole jar mass minus the empty jar to get a Quinn.

On Wednesday, I was absent.
On Thursday, we learned about a mole and molar mass. A mole is a group of particles that contains Avogadro's number of particles. Another definition is that it is the measurement that relates how much to how many. The last definition we gave it was a proportion of grams to the number of particles. One mol of Hydrogen. We learned that the molar masses are compared to Hydrogen. Molar mass is the same as the relative atomic mass relative to Hydrogen. This picture to the left shows some molar masses of some substances. Atomic mass unit, a.m.v., equals one Hydrogen unit to measure atoms. Relative atomic mass and molar mass are the same number, but different units. So we did a problem, it was this: 55.845 amv x 6.02 x 10^23 = 55.845 g. You can see in this problem the numbers are the same, but the units changed.
On Friday, we had a sub, so we did a worksheet. I did numbers one through three and my group got assigned number four. I did all the questions right I checked them using the answer key on google drive. I understand how to do these problems now. I know that you must know the atomic masses of the elements to solve the problems. I tweeted you number four on Friday during class.  I did one through three in my notebook.

Blog Week 19

On Monday, we did Zn + HCl Lab. But first we discussed the properties of gaseous substances, which were combustibility and flammability, which mean the same thing. For the lab we took the trough filled it with water, put a bell jar full of water over the hole and then had a flask of hydrochloric acid and we dropped zinc into it. Once the system was topped off with the cork, the bell jar captured the water. We wanted to find the mass, volume and density of the system before and after the we added the zinc. In my group though our stopper/cork was too small to close the system, so we did not get any measurements. On Tuesday, my group got a chance to redo the experiment and actually see the gas get collected and test if it was combustible. We found out that the gas made was combustible. Our observations from the experiment were that the hydrochloric acid looked like water, the flask got warm when we added zinc and after combustion the flask got colder. We then considered what the gas in the bell jar could be. We decided we had three options: hydrogen, chlorine, or zinc. We eliminated chlorine because it's a yellow color and a poison and we also eliminated zinc because it has a high boiling point. So, the gas made had to be hydrogen, because it was the last option left and H2 is combustible. But, as we tried to figure out our equation we noticed that a second compound was made ZnCl2. We also noticed that a third was mad that was H2O because the hydrogen combined with the oxygen in the air to create water. We know this because there was condensation inside the bell jar after combustion. The picture below shows the equation for this lab.

On Wednesday, I worked on the skills practice worksheet. I understood how to balance the equations, but other than that I wasn't sure how to complete the other things.
On Thursday, we talked about diatomic elements, they in pure element form and they come in pairs. We learned that when they join into other compounds the diatomic element become single atoms. We then talked about how H2O and H2O2 compared, we assumed that all their atoms were the same mass/size. So, we did an experiment to test our theory. We took Magnesium and set it on fire. But we measured the mass before and got .37g. After we combusted it we knew that it'd combine with the oxygen in the air to make 2mgO. So the mass after we combusted it was .45g. This proved that we can't assume atoms are the same size. Oxygen mass= 21% mass of mg.
On Friday, we had a snow day!!

Blog Week 18

On Monday, we didn't have school. On Tuesday, we went to computer lab. In the computer lab we did a virtual lab and answered questions. On Wednesday, we went over the virtual lab. We the learned that are diatomic gases and some of those are oxygen, chlorine gas and phlogiston.

In this picture we can see that there are two phs in each of the first two boxes and the last two. Then there are two Os in the third box and the last two boxes. We learned that if the we combined an O to each of the ph boxes we'd get a mystery gas.

In the next drawing we see that the mystery gas is water, which lead us to the conclusion that phlogiston is hydrogen. Which the picture to the right shows that it is in fact hydrogen. The equation is H2+O= 2H2O.

The picture to the right shows the equation for hydrogen chloride. It's H2+Cl2= 2HCl. This is the equation because you must spilt up have an equal amount in each box at the end, and to get that one H and one Cl had to be in each box which gave the gas HCl.

This picture to the right shows that if you were to have the equation 4H2 + 4Cl2 it would equal 8 HCl. It's that because, the equation H2+Cl2 it would equal 2HCl. So, we'd could multiply 2HCl by 4 and get 8HCl.

This picture to the right shows an equation with elements. We want to divide them up evenly. We can spilt compounds and make compounds to get the answer. We stopped here on Wednesday.

On Thursday, I left school early, not feeling well, so I missed the explanation.

On Friday, I had a doctor's appointment, I'm pretty sure I missed an assessment.